1/7(k-6)=3/7(k+4)

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Solution for 1/7(k-6)=3/7(k+4) equation: 


k in (-oo:+oo)

(1/7)*(k-6) = (3/7)*(k+4) // - (3/7)*(k+4)

(1/7)*(k-6)-((3/7)*(k+4)) = 0

(1/7)*(k-6)+(-3/7)*(k+4) = 0

1/7*(k-6)-3/7*(k+4) = 0

1/7*(k-6)-3/7*(k+4) = 0

-2/7*k-18/7 = 0

-2/7*k-18/7 = 0

-2/7*k-18/7 = 0 // + 18/7

-2/7*k = 18/7 // : -2/7

k = 18/7/(-2/7)

k = -9

k = -9

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