1/7(x+3)=2

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Solution for 1/7(x+3)=2 equation: 



1/7(x+3)=2

We move all terms to the left:

1/7(x+3)-(2)=0



Domain of the equation: 7(x+3)!=0

x∈R



We multiply all the terms by the denominator


-2*7(x+3)+1=0

Wy multiply elements

-14x(x+1=0

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