1/7(x+4)=1/21(3x+21)

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Solution for 1/7(x+4)=1/21(3x+21) equation:



1/7(x+4)=1/21(3x+21)
We move all terms to the left:
1/7(x+4)-(1/21(3x+21))=0
Domain of the equation: 7(x+4)!=0
x∈R
Domain of the equation: 21(3x+21))!=0
x∈R
We calculate fractions
(21x3/(7(x+4)*21(3x+21)))+(-7xx/(7(x+4)*21(3x+21)))=0
We calculate terms in parentheses: +(21x3/(7(x+4)*21(3x+21))), so:
21x3/(7(x+4)*21(3x+21))
We multiply all the terms by the denominator
21x3
We add all the numbers together, and all the variables
21x^3
We do not support expression: x^3

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