1/7(x+4)=1/21(3x+21)

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Solution for 1/7(x+4)=1/21(3x+21) equation: 



1/7(x+4)=1/21(3x+21)

We move all terms to the left:

1/7(x+4)-(1/21(3x+21))=0



Domain of the equation: 7(x+4)!=0

x∈R





Domain of the equation: 21(3x+21))!=0

x∈R



We calculate fractions


(21x3/(7(x+4)*21(3x+21)))+(-7xx/(7(x+4)*21(3x+21)))=0



We calculate terms in parentheses: +(21x3/(7(x+4)*21(3x+21))), so:

21x3/(7(x+4)*21(3x+21))

We multiply all the terms by the denominator


21x3

We add all the numbers together, and all the variables

21x^3

We do not support expression: x^3

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