1/7(x+7)=1/21(3x=21)

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Solution for 1/7(x+7)=1/21(3x=21) equation: 



1/7(x+7)=1/21(3x=21)

We move all terms to the left:

1/7(x+7)-(1/21(3x)=0



Domain of the equation: 7(x+7)!=0

x∈R





Domain of the equation: 213x!=0

x!=0/213

x!=0

x∈R



We calculate fractions


213x/(1491x^2+10437x)+(-7xx/(1491x^2+10437x)=0



We calculate terms in parentheses: +(-7xx/(1491x^2+10437x), so:

-7xx/(1491x^2+10437x

We multiply all the terms by the denominator


-7xx

Back to the equation:

+(-7xx)



We get rid of parentheses

213x/(1491x^2+10437x)-7xx=0

We multiply all the terms by the denominator


213x-7xx*(1491x^2+10437x)=0

We multiply parentheses

-10437x^3-73059x^2+213x=0

We do not support expression: x^3

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