1/7(x+7)=1/21(3x=21)

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Solution for 1/7(x+7)=1/21(3x=21) equation:



1/7(x+7)=1/21(3x=21)
We move all terms to the left:
1/7(x+7)-(1/21(3x)=0
Domain of the equation: 7(x+7)!=0
x∈R
Domain of the equation: 213x!=0
x!=0/213
x!=0
x∈R
We calculate fractions
213x/(1491x^2+10437x)+(-7xx/(1491x^2+10437x)=0
We calculate terms in parentheses: +(-7xx/(1491x^2+10437x), so:
-7xx/(1491x^2+10437x
We multiply all the terms by the denominator
-7xx
Back to the equation:
+(-7xx)
We get rid of parentheses
213x/(1491x^2+10437x)-7xx=0
We multiply all the terms by the denominator
213x-7xx*(1491x^2+10437x)=0
We multiply parentheses
-10437x^3-73059x^2+213x=0
We do not support expression: x^3

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