1/7(x-8)=-16-2

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Solution for 1/7(x-8)=-16-2 equation:



1/7(x-8)=-16-2
We move all terms to the left:
1/7(x-8)-(-16-2)=0
Domain of the equation: 7(x-8)!=0
x∈R
We add all the numbers together, and all the variables
1/7(x-8)-(-18)=0
We add all the numbers together, and all the variables
1/7(x-8)+18=0
We multiply all the terms by the denominator
18*7(x-8)+1=0
Wy multiply elements
126x(x+1=0

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