1/7(x-8)=-16-2

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Solution for 1/7(x-8)=-16-2 equation: 



1/7(x-8)=-16-2

We move all terms to the left:

1/7(x-8)-(-16-2)=0



Domain of the equation: 7(x-8)!=0

x∈R



We add all the numbers together, and all the variables

1/7(x-8)-(-18)=0

We add all the numbers together, and all the variables

1/7(x-8)+18=0

We multiply all the terms by the denominator


18*7(x-8)+1=0

Wy multiply elements

126x(x+1=0

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