If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/7+2x/3=1/3(15x-3)
We move all terms to the left:
1/7+2x/3-(1/3(15x-3))=0
Domain of the equation: 3(15x-3))!=0We calculate fractions
x∈R
14x/(63x1+()/(63x1+27x/(63x1=0
We can not solve this equation
| d•5=8.62 | | 4x+154=-5x+46 | | 7d=17 | | 2(-17x+x)=-14 | | x-2/5=1/15 | | 8x/3-2=30 | | 4x+3=270 | | 3/7z=-9 | | d•6=7.3 | | 4x+3=540 | | 2(x+2)=7(x-1)+9 | | 42=49-u | | x/2.3=7.1 | | Y=0.8x+1.2 | | v-39=6 | | -0.7a=49 | | m-5m-3m+5=-7m+5 | | 95=19^x | | x-13.7=-6.4 | | 3^x+2=8 | | x^2-8x-209=0 | | 4x+3+9x-47=180 | | x+4.8=-7.5 | | 60+(14x-20)=180 | | 2.4p=2/3 | | 36-2x=-8-6(5x+2) | | (7/8)x-3+(1/4)x=(7/32)x+(1/8) | | (-2p)-3=-19 | | 11x-65=58 | | 1/4p-(1-1/3p)=0 | | y=12y+60 | | 4(x-7)=-40 |