1/7k-3=3/7k+7

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Solution for 1/7k-3=3/7k+7 equation: 



1/7k-3=3/7k+7

We move all terms to the left:

1/7k-3-(3/7k+7)=0



Domain of the equation: 7k!=0

k!=0/7

k!=0

k∈R





Domain of the equation: 7k+7)!=0

k∈R



We get rid of parentheses

1/7k-3/7k-7-3=0

We multiply all the terms by the denominator


-7*7k-3*7k+1-3=0

We add all the numbers together, and all the variables

-7*7k-3*7k-2=0

Wy multiply elements

-49k-21k-2=0

We add all the numbers together, and all the variables

-70k-2=0

We move all terms containing k to the left, all other terms to the right

-70k=2

k=2/-70

k=-1/35

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