1/7k-4=3/7k+6

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Solution for 1/7k-4=3/7k+6 equation: 



1/7k-4=3/7k+6

We move all terms to the left:

1/7k-4-(3/7k+6)=0



Domain of the equation: 7k!=0

k!=0/7

k!=0

k∈R





Domain of the equation: 7k+6)!=0

k∈R



We get rid of parentheses

1/7k-3/7k-6-4=0

We multiply all the terms by the denominator


-6*7k-4*7k+1-3=0

We add all the numbers together, and all the variables

-6*7k-4*7k-2=0

Wy multiply elements

-42k-28k-2=0

We add all the numbers together, and all the variables

-70k-2=0

We move all terms containing k to the left, all other terms to the right

-70k=2

k=2/-70

k=-1/35

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