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1/7m=5m
We move all terms to the left:
1/7m-(5m)=0
Domain of the equation: 7m!=0We add all the numbers together, and all the variables
m!=0/7
m!=0
m∈R
-5m+1/7m=0
We multiply all the terms by the denominator
-5m*7m+1=0
Wy multiply elements
-35m^2+1=0
a = -35; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-35)·1
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{35}}{2*-35}=\frac{0-2\sqrt{35}}{-70} =-\frac{2\sqrt{35}}{-70} =-\frac{\sqrt{35}}{-35} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{35}}{2*-35}=\frac{0+2\sqrt{35}}{-70} =\frac{2\sqrt{35}}{-70} =\frac{\sqrt{35}}{-35} $
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