1/7t+5=2

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Solution for 1/7t+5=2 equation:



1/7t+5=2
We move all terms to the left:
1/7t+5-(2)=0
Domain of the equation: 7t!=0
t!=0/7
t!=0
t∈R
We add all the numbers together, and all the variables
1/7t+3=0
We multiply all the terms by the denominator
3*7t+1=0
Wy multiply elements
21t+1=0
We move all terms containing t to the left, all other terms to the right
21t=-1
t=-1/21
t=-1/21

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