1/7x+5/7x+3=27

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Solution for 1/7x+5/7x+3=27 equation: 



1/7x+5/7x+3=27

We move all terms to the left:

1/7x+5/7x+3-(27)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We add all the numbers together, and all the variables

1/7x+5/7x-24=0

We multiply all the terms by the denominator


-24*7x+1+5=0

We add all the numbers together, and all the variables

-24*7x+6=0

Wy multiply elements

-168x+6=0

We move all terms containing x to the left, all other terms to the right

-168x=-6

x=-6/-168

x=1/28

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