1/7x-10=2(x-50)-27

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Solution for 1/7x-10=2(x-50)-27 equation: 



1/7x-10=2(x-50)-27

We move all terms to the left:

1/7x-10-(2(x-50)-27)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We multiply all the terms by the denominator


-((2(x-50)-27))*7x-10*7x+1=0

Wy multiply elements

-((2(x-50)-27))*7x-70x+1=0

We add all the numbers together, and all the variables

-70x-((2(x-50)-27))*7x+1=0

We move all terms containing x to the left, all other terms to the right

-70x-((2(x-50)-27))*7x=-1

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