1/7x-10=2(x-50)-27

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Solution for 1/7x-10=2(x-50)-27 equation:



1/7x-10=2(x-50)-27
We move all terms to the left:
1/7x-10-(2(x-50)-27)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
We multiply all the terms by the denominator
-((2(x-50)-27))*7x-10*7x+1=0
Wy multiply elements
-((2(x-50)-27))*7x-70x+1=0
We add all the numbers together, and all the variables
-70x-((2(x-50)-27))*7x+1=0
We move all terms containing x to the left, all other terms to the right
-70x-((2(x-50)-27))*7x=-1

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