1/7x-3=16

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Solution for 1/7x-3=16 equation: 



1/7x-3=16

We move all terms to the left:

1/7x-3-(16)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We add all the numbers together, and all the variables

1/7x-19=0

We multiply all the terms by the denominator


-19*7x+1=0

Wy multiply elements

-133x+1=0

We move all terms containing x to the left, all other terms to the right

-133x=-1

x=-1/-133

x=1/133

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