1/7x2+22=15

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Solution for 1/7x2+22=15 equation: 



1/7x^2+22=15

We move all terms to the left:

1/7x^2+22-(15)=0



Domain of the equation: 7x^2!=0

x^2!=0/7

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

1/7x^2+7=0

We multiply all the terms by the denominator


7*7x^2+1=0

Wy multiply elements

49x^2+1=0

a = 49; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·49·1
Δ = -196
Delta is less than zero, so there is no solution for the equation

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