1/7x=x-18

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Solution for 1/7x=x-18 equation:



1/7x=x-18
We move all terms to the left:
1/7x-(x-18)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
We get rid of parentheses
1/7x-x+18=0
We multiply all the terms by the denominator
-x*7x+18*7x+1=0
Wy multiply elements
-7x^2+126x+1=0
a = -7; b = 126; c = +1;
Δ = b2-4ac
Δ = 1262-4·(-7)·1
Δ = 15904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{15904}=\sqrt{16*994}=\sqrt{16}*\sqrt{994}=4\sqrt{994}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-4\sqrt{994}}{2*-7}=\frac{-126-4\sqrt{994}}{-14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+4\sqrt{994}}{2*-7}=\frac{-126+4\sqrt{994}}{-14} $

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