1/8(128+x)=27

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Solution for 1/8(128+x)=27 equation: 



1/8(128+x)=27

We move all terms to the left:

1/8(128+x)-(27)=0



Domain of the equation: 8(128+x)!=0

x∈R



We add all the numbers together, and all the variables

1/8(x+128)-27=0

We multiply all the terms by the denominator


-27*8(x+128)+1=0

Wy multiply elements

-216x(x+1=0

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