1/8(2x-16)-3/4x=x+10

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Solution for 1/8(2x-16)-3/4x=x+10 equation:



1/8(2x-16)-3/4x=x+10
We move all terms to the left:
1/8(2x-16)-3/4x-(x+10)=0
Domain of the equation: 8(2x-16)!=0
x∈R
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
We get rid of parentheses
1/8(2x-16)-3/4x-x-10=0
We calculate fractions
-x+4x/(64x^2-512x)+(-24x2/(64x^2-512x)-10=0
We add all the numbers together, and all the variables
-1x+4x/(64x^2-512x)+(-24x2/(64x^2-512x)-10=0
We calculate fractions
We do not support expression: x^3

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