1/8(3*k-2)=1/4(k+5)

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Solution for 1/8(3*k-2)=1/4(k+5) equation: 



1/8(3k-2)=1/4(k+5)

We move all terms to the left:

1/8(3k-2)-(1/4(k+5))=0



Domain of the equation: 8(3k-2)!=0

k∈R





Domain of the equation: 4(k+5))!=0

k∈R



We calculate fractions


(4kk/(8(3k-2)*4(k+5)))+(-8k3/(8(3k-2)*4(k+5)))=0



We calculate terms in parentheses: +(4kk/(8(3k-2)*4(k+5))), so:

4kk/(8(3k-2)*4(k+5))

We multiply all the terms by the denominator


4kk

Back to the equation:

+(4kk)





We calculate terms in parentheses: +(-8k3/(8(3k-2)*4(k+5))), so:

-8k3/(8(3k-2)*4(k+5))

We multiply all the terms by the denominator


-8k3

We add all the numbers together, and all the variables

-8k^3

We do not support ekpression: k^3

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