1/8(3d-2)=1/2(d+5)

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Solution for 1/8(3d-2)=1/2(d+5) equation: 



1/8(3d-2)=1/2(d+5)

We move all terms to the left:

1/8(3d-2)-(1/2(d+5))=0



Domain of the equation: 8(3d-2)!=0

d∈R





Domain of the equation: 2(d+5))!=0

d∈R



We calculate fractions


(2dd/(8(3d-2)*2(d+5)))+(-8d3/(8(3d-2)*2(d+5)))=0



We calculate terms in parentheses: +(2dd/(8(3d-2)*2(d+5))), so:

2dd/(8(3d-2)*2(d+5))

We multiply all the terms by the denominator


2dd

Back to the equation:

+(2dd)





We calculate terms in parentheses: +(-8d3/(8(3d-2)*2(d+5))), so:

-8d3/(8(3d-2)*2(d+5))

We multiply all the terms by the denominator


-8d3

We add all the numbers together, and all the variables

-8d^3

We do not support edpression: d^3

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