1/8(3y+2)=1/4(2y+1/2)+1/2

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Solution for 1/8(3y+2)=1/4(2y+1/2)+1/2 equation:


y in (-oo:+oo)

(1/8)*(3*y+2) = (1/4)*(2*y+1/2)+1/2 // - (1/4)*(2*y+1/2)+1/2

(1/8)*(3*y+2)-((1/4)*(2*y+1/2))-(1/2) = 0

(1/8)*(3*y+2)+(-1/4)*(2*y+1/2)-1/2 = 0

1/8*(3*y+2)-1/4*(2*y+1/2)-1/2 = 0

(1/8*2*(3*y+2))/2+(-1/4*2*(2*y+1/2))/2-1/2 = 0

1/8*2*(3*y+2)-1/4*2*(2*y+1/2)-1 = 0

1/4-1/4*y-1 = 0

-1/4*y-3/4 = 0

(-1/4*y-3/4)/2 = 0

(-1/4*y-3/4)/2 = 0 // * 2

-1/4*y-3/4 = 0

-1/4*y-3/4 = 0 // + 3/4

-1/4*y = 3/4 // : -1/4

y = 3/4/(-1/4)

y = -3

y = -3

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