1/8(40+16)=9(2x-1)-5

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Solution for 1/8(40+16)=9(2x-1)-5 equation:



1/8(40+16)=9(2x-1)-5
We move all terms to the left:
1/8(40+16)-(9(2x-1)-5)=0
We add all the numbers together, and all the variables
-(9(2x-1)-5)+1/856=0
We multiply all the terms by the denominator
-((9(2x-1)-5))*856+1=0
We move all terms containing x to the left, all other terms to the right
-((9(2x-1)-5))*856=-1

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