1/8(40x+16=9x-7(2x-1)-5

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Solution for 1/8(40x+16=9x-7(2x-1)-5 equation: 



1/8(40x+16=9x-7(2x-1)-5

We move all terms to the left:

1/8(40x+16-(9x-7(2x-1)-5)=0



Domain of the equation: 8(40x+16-(9x-7(2x-1)-5)!=0

x∈R



We multiply all the terms by the denominator


1!=0

There is no solution for this equation

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