1/8(40x+16=9x-7(2x-1-5

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Solution for 1/8(40x+16=9x-7(2x-1-5 equation: 



1/8(40x+16=9x-7(2x-1-5

We move all terms to the left:

1/8(40x+16-(9x-7(2x-1-5)=0



Domain of the equation: 8(40x+16-(9x-7(2x-1-5)!=0

x∈R



We add all the numbers together, and all the variables

1/8(40x+16-(9x-7(2x-6)=0

We multiply all the terms by the denominator


1!=0

There is no solution for this equation

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