1/8(5n+64)=1/4(20+2n)

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Solution for 1/8(5n+64)=1/4(20+2n) equation: 



1/8(5n+64)=1/4(20+2n)

We move all terms to the left:

1/8(5n+64)-(1/4(20+2n))=0



Domain of the equation: 8(5n+64)!=0

n∈R





Domain of the equation: 4(20+2n))!=0

n∈R



We add all the numbers together, and all the variables

1/8(5n+64)-(1/4(2n+20))=0

We calculate fractions


(4n2/(8(5n+64)*4(2n+20)))+(-8n5/(8(5n+64)*4(2n+20)))=0



We calculate terms in parentheses: +(4n2/(8(5n+64)*4(2n+20))), so:

4n2/(8(5n+64)*4(2n+20))

We multiply all the terms by the denominator


4n2

We add all the numbers together, and all the variables

4n^2

Back to the equation:

+(4n^2)





We calculate terms in parentheses: +(-8n5/(8(5n+64)*4(2n+20))), so:

-8n5/(8(5n+64)*4(2n+20))

We multiply all the terms by the denominator


-8n5

We add all the numbers together, and all the variables

-8n^5

We do not support enpression: n^5

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