1/8(5x+64)=1/2(20+2x)

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Solution for 1/8(5x+64)=1/2(20+2x) equation: 



1/8(5x+64)=1/2(20+2x)

We move all terms to the left:

1/8(5x+64)-(1/2(20+2x))=0



Domain of the equation: 8(5x+64)!=0

x∈R





Domain of the equation: 2(20+2x))!=0

x∈R



We add all the numbers together, and all the variables

1/8(5x+64)-(1/2(2x+20))=0

We calculate fractions


(2x2/(8(5x+64)*2(2x+20)))+(-8x5/(8(5x+64)*2(2x+20)))=0



We calculate terms in parentheses: +(2x2/(8(5x+64)*2(2x+20))), so:

2x2/(8(5x+64)*2(2x+20))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-8x5/(8(5x+64)*2(2x+20))), so:

-8x5/(8(5x+64)*2(2x+20))

We multiply all the terms by the denominator


-8x5

We add all the numbers together, and all the variables

-8x^5

We do not support expression: x^5

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