1/8(5x+7x)+15=1/4(x-24)

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Solution for 1/8(5x+7x)+15=1/4(x-24) equation: 



1/8(5x+7x)+15=1/4(x-24)

We move all terms to the left:

1/8(5x+7x)+15-(1/4(x-24))=0



Domain of the equation: 8(5x+7x)!=0

x∈R





Domain of the equation: 4(x-24))!=0

x∈R



We add all the numbers together, and all the variables

1/8(+12x)-(1/4(x-24))+15=0

We calculate fractions


(4xx/(8(+12x)*4(x-24)))+(-8x0/(8(+12x)*4(x-24)))+15=0



We calculate terms in parentheses: +(4xx/(8(+12x)*4(x-24))), so:

4xx/(8(+12x)*4(x-24))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-8x0/(8(+12x)*4(x-24))), so:

-8x0/(8(+12x)*4(x-24))

We multiply all the terms by the denominator


-8x0

We add all the numbers together, and all the variables

-8x

Back to the equation:

+(-8x)



We get rid of parentheses

4xx-8x+15=0

We add all the numbers together, and all the variables

-8x+4xx+15=0

We move all terms containing x to the left, all other terms to the right

-8x+4xx=-15

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