1/8(5y+64)=2/8(20+2y)

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Solution for 1/8(5y+64)=2/8(20+2y) equation: 



1/8(5y+64)=2/8(20+2y)

We move all terms to the left:

1/8(5y+64)-(2/8(20+2y))=0



Domain of the equation: 8(5y+64)!=0

y∈R





Domain of the equation: 8(20+2y))!=0

y∈R



We add all the numbers together, and all the variables

1/8(5y+64)-(2/8(2y+20))=0

We calculate fractions


(8y2/(8(5y+64)*8(2y+20)))+(-16y5/(8(5y+64)*8(2y+20)))=0



We calculate terms in parentheses: +(8y2/(8(5y+64)*8(2y+20))), so:

8y2/(8(5y+64)*8(2y+20))

We multiply all the terms by the denominator


8y2

We add all the numbers together, and all the variables

8y^2

Back to the equation:

+(8y^2)





We calculate terms in parentheses: +(-16y5/(8(5y+64)*8(2y+20))), so:

-16y5/(8(5y+64)*8(2y+20))

We multiply all the terms by the denominator


-16y5

We add all the numbers together, and all the variables

-16y^5

We do not support eypression: y^5

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