1/8(6q-5)=3/4q-7/8

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Solution for 1/8(6q-5)=3/4q-7/8 equation: 


q in (-oo:+oo)

(1/8)*(6*q-5) = (3/4)*q-(7/8) // - (3/4)*q-(7/8)

(1/8)*(6*q-5)-((3/4)*q)+7/8 = 0

(1/8)*(6*q-5)+(-3/4)*q+7/8 = 0

1/8*(6*q-5)+(-3*q)/4+7/8 = 0

(1/8*4*8*(6*q-5))/(4*8)+(-3*8*q)/(4*8)+(4*7)/(4*8) = 0

1/8*4*8*(6*q-5)-3*8*q+4*7 = 0

28-20 = 0

8 = 0

8/(4*8) = 0

8/(4*8) = 0 // * 4*8

8 = 0

q belongs to the empty set

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