1/8(7t-7)=1/16(t+7)

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Solution for 1/8(7t-7)=1/16(t+7) equation:



1/8(7t-7)=1/16(t+7)
We move all terms to the left:
1/8(7t-7)-(1/16(t+7))=0
Domain of the equation: 8(7t-7)!=0
t∈R
Domain of the equation: 16(t+7))!=0
t∈R
We calculate fractions
(16tt/(8(7t-7)*16(t+7)))+(-8t7/(8(7t-7)*16(t+7)))=0
We calculate terms in parentheses: +(16tt/(8(7t-7)*16(t+7))), so:
16tt/(8(7t-7)*16(t+7))
We multiply all the terms by the denominator
16tt
Back to the equation:
+(16tt)
We calculate terms in parentheses: +(-8t7/(8(7t-7)*16(t+7))), so:
-8t7/(8(7t-7)*16(t+7))
We multiply all the terms by the denominator
-8t7
We add all the numbers together, and all the variables
-8t^7
We do not support etpression: t^7

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