1/8(8y+16)-7=-1/8(-16y-32)

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Solution for 1/8(8y+16)-7=-1/8(-16y-32) equation: 



1/8(8y+16)-7=-1/8(-16y-32)

We move all terms to the left:

1/8(8y+16)-7-(-1/8(-16y-32))=0



Domain of the equation: 8(8y+16)!=0

y∈R





Domain of the equation: 8(-16y-32))!=0

y∈R



We calculate fractions


(8y(-)/(8(8y+16)*8(-16y-32)))+(-(-8y8)/(8(8y+16)*8(-16y-32)))-7=0



We calculate terms in parentheses: +(8y(-)/(8(8y+16)*8(-16y-32))), so:

8y(-)/(8(8y+16)*8(-16y-32))

We add all the numbers together, and all the variables

8y0/(8(8y+16)*8(-16y-32))

We multiply all the terms by the denominator


8y0

We add all the numbers together, and all the variables

8y

Back to the equation:

+(8y)





We calculate terms in parentheses: +(-(-8y8)/(8(8y+16)*8(-16y-32))), so:

-(-8y8)/(8(8y+16)*8(-16y-32))

We add all the numbers together, and all the variables

-(-8y^8)/(8(8y+16)*8(-16y-32))

We multiply all the terms by the denominator


-(-8y^8)

We do not support eypression: y^8

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