1/8(a+6)=1/2(4-a)

Solution for 1/8(a+6)=1/2(4-a) equation:

1/8(a+6)=1/2(4-a)

We move all terms to the left:

1/8(a+6)-(1/2(4-a))=0


Domain of the equation: 8(a+6)!=0

a∈R



Domain of the equation: 2(4-a))!=0

a∈R


We add all the numbers together, and all the variables

1/8(a+6)-(1/2(-1a+4))=0

We calculate fractions


(2a(-)/(8(a+6)*2(-1a+4)))+(-8aa/(8(a+6)*2(-1a+4)))=0


We calculate terms in parentheses: +(2a(-)/(8(a+6)*2(-1a+4))), so:

2a(-)/(8(a+6)*2(-1a+4))

We add all the numbers together, and all the variables

2a0/(8(a+6)*2(-1a+4))

We multiply all the terms by the denominator


2a0

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)



We calculate terms in parentheses: +(-8aa/(8(a+6)*2(-1a+4))), so:

-8aa/(8(a+6)*2(-1a+4))

We multiply all the terms by the denominator


-8aa

Back to the equation:

+(-8aa)


We get rid of parentheses

2a-8aa=0