1/8(x+4)=2x-3(4-x)-7

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Solution for 1/8(x+4)=2x-3(4-x)-7 equation: 


x in (-oo:+oo)

(1/8)*(x+4) = 2*x-(3*(4-x))-7 // - 2*x-(3*(4-x))-7

(1/8)*(x+4)+3*(4-x)-(2*x)+7 = 0

(1/8)*(x+4)+3*(4-x)-2*x+7 = 0

1/8*(x+4)+3*(4-x)-2*x+7 = 0

1/8*(x+4)+3*(4-x)-2*x+7 = 0

7-23/8*x-2*x+25/2 = 0

7-39/8*x+25/2 = 0

39/2-39/8*x = 0

39/2-39/8*x = 0

39/2-39/8*x = 0 // - 39/2

-39/8*x = -39/2 // : -39/8

x = -39/2/(-39/8)

x = 4

x = 4

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