1/8(x+6)=2/3(x-9)

Solution for 1/8(x+6)=2/3(x-9) equation:

1/8(x+6)=2/3(x-9)

We move all terms to the left:

1/8(x+6)-(2/3(x-9))=0


Domain of the equation: 8(x+6)!=0

x∈R



Domain of the equation: 3(x-9))!=0

x∈R


We calculate fractions


(3xx/(8(x+6)*3(x-9)))+(-16xx/(8(x+6)*3(x-9)))=0


We calculate terms in parentheses: +(3xx/(8(x+6)*3(x-9))), so:

3xx/(8(x+6)*3(x-9))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-16xx/(8(x+6)*3(x-9))), so:

-16xx/(8(x+6)*3(x-9))

We multiply all the terms by the denominator


-16xx

Back to the equation:

+(-16xx)


We get rid of parentheses

3xx-16xx=0