1/8(x+9)=1/3(5-x)

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Solution for 1/8(x+9)=1/3(5-x) equation: 



1/8(x+9)=1/3(5-x)

We move all terms to the left:

1/8(x+9)-(1/3(5-x))=0



Domain of the equation: 8(x+9)!=0

x∈R





Domain of the equation: 3(5-x))!=0

x∈R



We add all the numbers together, and all the variables

1/8(x+9)-(1/3(-1x+5))=0

We calculate fractions


(3x(-)/(8(x+9)*3(-1x+5)))+(-8xx/(8(x+9)*3(-1x+5)))=0



We calculate terms in parentheses: +(3x(-)/(8(x+9)*3(-1x+5))), so:

3x(-)/(8(x+9)*3(-1x+5))

We add all the numbers together, and all the variables

3x0/(8(x+9)*3(-1x+5))

We multiply all the terms by the denominator


3x0

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-8xx/(8(x+9)*3(-1x+5))), so:

-8xx/(8(x+9)*3(-1x+5))

We multiply all the terms by the denominator


-8xx

Back to the equation:

+(-8xx)



We get rid of parentheses

3x-8xx=0

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