1/8(x-2)=1/3(3x+1)

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Solution for 1/8(x-2)=1/3(3x+1) equation: 



1/8(x-2)=1/3(3x+1)

We move all terms to the left:

1/8(x-2)-(1/3(3x+1))=0



Domain of the equation: 8(x-2)!=0

x∈R





Domain of the equation: 3(3x+1))!=0

x∈R



We calculate fractions


(3x3/(8(x-2)*3(3x+1)))+(-8xx/(8(x-2)*3(3x+1)))=0



We calculate terms in parentheses: +(3x3/(8(x-2)*3(3x+1))), so:

3x3/(8(x-2)*3(3x+1))

We multiply all the terms by the denominator


3x3

We add all the numbers together, and all the variables

3x^3

We do not support expression: x^3

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