1/8(x-4)=7+2x

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Solution for 1/8(x-4)=7+2x equation: 



1/8(x-4)=7+2x

We move all terms to the left:

1/8(x-4)-(7+2x)=0



Domain of the equation: 8(x-4)!=0

x∈R



We add all the numbers together, and all the variables

1/8(x-4)-(2x+7)=0

We get rid of parentheses

1/8(x-4)-2x-7=0

We multiply all the terms by the denominator


-2x*8(x-4)-7*8(x-4)+1=0

Wy multiply elements

-16x^2(x-56x(x+1=0

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