1/8(z-1)=-2/3(z+3)

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Solution for 1/8(z-1)=-2/3(z+3) equation: 



1/8(z-1)=-2/3(z+3)

We move all terms to the left:

1/8(z-1)-(-2/3(z+3))=0



Domain of the equation: 8(z-1)!=0

z∈R





Domain of the equation: 3(z+3))!=0

z∈R



We calculate fractions


(3zz/(8(z-1)*3(z+3)))+(-(-16zz)/(8(z-1)*3(z+3)))=0



We calculate terms in parentheses: +(3zz/(8(z-1)*3(z+3))), so:

3zz/(8(z-1)*3(z+3))

We multiply all the terms by the denominator


3zz

Back to the equation:

+(3zz)





We calculate terms in parentheses: +(-(-16zz)/(8(z-1)*3(z+3))), so:

-(-16zz)/(8(z-1)*3(z+3))

We multiply all the terms by the denominator


-(-16zz)

We get rid of parentheses

16zz

Back to the equation:

+(16zz)

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