If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
((3*(1/8))/4)*x = 1/16 // - 1/16
((3*(1/8))/4)*x-(1/16) = 0
((3*(1/8))/4)*x-1/16 = 0
3/32*x-1/16 = 0 // + 1/16
3/32*x = 1/16 // : 3/32
x = 1/16/3/32
x = 2/3
x = 2/3
| x^2+2n-3=48 | | (2z-4)(3z+10)= | | h/-6-12 | | 4.9x^2+2.3x-10=0 | | 20=5b-(100+3b) | | 10(y-2)=18y+5 | | v=200+50(85-70) | | 10p^2-3p-97=3p | | 4x+13=8x-7 | | k^12x+23=0 | | -3/5z=-6 | | -3x+2(-3-2x)=-6-7x | | (2x+8)(x-6)+3(x-2)=0 | | (9x+4)*(5x-2)=0 | | 4(3+c)-(2-c)= | | 50X^2-1X-10=0 | | 8y-(5y+13)=-7 | | 0.33=log(x) | | 6x^2-121= | | 2.5n-1.04=0.15n-0.1 | | 4x^2+13x+27=7x+6 | | 4.9x^2+2.3x-180=0 | | (5x^2+5x-7)+(2x^2+9x+12)-(7x^2-15)= | | 16-8x-x^2=0 | | 2=2(2x-5) | | -[4x-(2x+3)]=-4-[3(2x-4)-2x] | | y=(c-k)x+2 | | x+0.2=0.36 | | cos^2(2x)=.5 | | ln(10x-1)=-1 | | 5(3x-2(2x-6)-(3x-1))=90 | | (2x-5)=(30+42) |