1/8X+2=2x

Solution for 1/8X+2=2x equation:

1/8X+2=2X

We move all terms to the left:

1/8X+2-(2X)=0


Domain of the equation: 8X!=0

X!=0/8

X!=0

X∈R


We add all the numbers together, and all the variables

-2X+1/8X+2=0

We multiply all the terms by the denominator


-2X*8X+2*8X+1=0

Wy multiply elements

-16X^2+16X+1=0

a = -16; b = 16; c = +1;
Δ = b2-4ac
Δ = 162-4·(-16)·1
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{5}}{2*-16}=\frac{-16-8\sqrt{5}}{-32}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{5}}{2*-16}=\frac{-16+8\sqrt{5}}{-32}
$