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1/8t+(1/12)t=1
We move all terms to the left:
1/8t+(1/12)t-(1)=0
Domain of the equation: 8t!=0
t!=0/8
t!=0
t∈R
Domain of the equation: 12)t!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
1/8t+(+1/12)t-1=0
We multiply parentheses
t^2+1/8t-1=0
We multiply all the terms by the denominator
t^2*8t-1*8t+1=0
Wy multiply elements
8t^3-8t+1=0
We do not support etpression: t^3
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