1/8x+12-3/2=3x-8+3/4x

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Solution for 1/8x+12-3/2=3x-8+3/4x equation:



1/8x+12-3/2=3x-8+3/4x
We move all terms to the left:
1/8x+12-3/2-(3x-8+3/4x)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 4x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
1/8x-(3x+3/4x-8)+12-3/2=0
We get rid of parentheses
1/8x-3x-3/4x+8+12-3/2=0
We calculate fractions
(-384x^2)/128x^2-3x+16x/128x^2+(-96x)/128x^2+8+12=0
We add all the numbers together, and all the variables
(-384x^2)/128x^2-3x+16x/128x^2+(-96x)/128x^2+20=0
We multiply all the terms by the denominator
(-384x^2)-3x*128x^2+16x+(-96x)+20*128x^2=0
We add all the numbers together, and all the variables
(-384x^2)+16x-3x*128x^2+(-96x)+20*128x^2=0
Wy multiply elements
(-384x^2)-384x^3+2560x^2+16x+(-96x)=0
We get rid of parentheses
-384x^2-384x^3+2560x^2+16x-96x=0
We do not support expression: x^3

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