1/8x+240=1/2x

Solution for 1/8x+240=1/2x equation:

1/8x+240=1/2x

We move all terms to the left:

1/8x+240-(1/2x)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/8x-(+1/2x)+240=0

We get rid of parentheses

1/8x-1/2x+240=0

We calculate fractions


2x/16x^2+(-8x)/16x^2+240=0

We multiply all the terms by the denominator


2x+(-8x)+240*16x^2=0

Wy multiply elements

3840x^2+2x+(-8x)=0

We get rid of parentheses

3840x^2+2x-8x=0

We add all the numbers together, and all the variables

3840x^2-6x=0

a = 3840; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·3840·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*3840}=\frac{0}{7680}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*3840}=\frac{12}{7680}
=1/640
$