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1/8x+3/5x=87
We move all terms to the left:
1/8x+3/5x-(87)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
5x/40x^2+24x/40x^2-87=0
We multiply all the terms by the denominator
5x+24x-87*40x^2=0
We add all the numbers together, and all the variables
29x-87*40x^2=0
Wy multiply elements
-3480x^2+29x=0
a = -3480; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-3480)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-3480}=\frac{-58}{-6960} =1/120 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-3480}=\frac{0}{-6960} =0 $
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