1/8x-1/9x+1/72=8

Solution for 1/8x-1/9x+1/72=8 equation:

1/8x-1/9x+1/72=8

We move all terms to the left:

1/8x-1/9x+1/72-(8)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 9x!=0

x!=0/9

x!=0

x∈R


determiningTheFunctionDomain
1/8x-1/9x-8+1/72=0

We calculate fractions


648x^2/36288x^2+4536x/36288x^2+(-4032x)/36288x^2-8=0

We multiply all the terms by the denominator


648x^2+4536x+(-4032x)-8*36288x^2=0

Wy multiply elements

648x^2-290304x^2+4536x+(-4032x)=0

We get rid of parentheses

648x^2-290304x^2+4536x-4032x=0

We add all the numbers together, and all the variables

-289656x^2+504x=0

a = -289656; b = 504; c = 0;
Δ = b2-4ac
Δ = 5042-4·(-289656)·0
Δ = 254016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{254016}=504$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(504)-504}{2*-289656}=\frac{-1008}{-579312}
=7/4023
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(504)+504}{2*-289656}=\frac{0}{-579312}
=0
$