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1/8x-4=x
We move all terms to the left:
1/8x-4-(x)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
-1x+1/8x-4=0
We multiply all the terms by the denominator
-1x*8x-4*8x+1=0
Wy multiply elements
-8x^2-32x+1=0
a = -8; b = -32; c = +1;
Δ = b2-4ac
Δ = -322-4·(-8)·1
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{66}}{2*-8}=\frac{32-4\sqrt{66}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{66}}{2*-8}=\frac{32+4\sqrt{66}}{-16} $
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