1/9(18y+27)-5=-1/5(5y-20)

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Solution for 1/9(18y+27)-5=-1/5(5y-20) equation: 


y in (-oo:+oo)

(1/9)*(18*y+27)-5 = (-1/5)*(5*y-20) // - (-1/5)*(5*y-20)

(1/9)*(18*y+27)-((-1/5)*(5*y-20))-5 = 0

(1/9)*(18*y+27)+(1/5)*(5*y-20)-5 = 0

1/9*(18*y+27)+1/5*(5*y-20)-5 = 0

1/9*(18*y+27)+1/5*(5*y-20)-5 = 0

3*y-5-1 = 0

3*y-6 = 0

3*y-6 = 0

3*y-6 = 0 // + 6

3*y = 6 // : 3

y = 6/3

y = 2

y = 2

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