1/9(2m-16)-16=1/3(2m+4)

Solution for 1/9(2m-16)-16=1/3(2m+4) equation:

1/9(2m-16)-16=1/3(2m+4)

We move all terms to the left:

1/9(2m-16)-16-(1/3(2m+4))=0


Domain of the equation: 9(2m-16)!=0

m∈R



Domain of the equation: 3(2m+4))!=0

m∈R


We calculate fractions


(3m2/(9(2m-16)*3(2m+4)))+(-9m2/(9(2m-16)*3(2m+4)))-16=0


We calculate terms in parentheses: +(3m2/(9(2m-16)*3(2m+4))), so:

3m2/(9(2m-16)*3(2m+4))

We multiply all the terms by the denominator


3m2

We add all the numbers together, and all the variables

3m^2

Back to the equation:

+(3m^2)



We calculate terms in parentheses: +(-9m2/(9(2m-16)*3(2m+4))), so:

-9m2/(9(2m-16)*3(2m+4))

We multiply all the terms by the denominator


-9m2

We add all the numbers together, and all the variables

-9m^2

Back to the equation:

+(-9m^2)


We add all the numbers together, and all the variables

3m^2+(-9m^2)-16=0

We get rid of parentheses

3m^2-9m^2-16=0

We add all the numbers together, and all the variables

-6m^2-16=0

a = -6; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-6)·(-16)
Δ = -384
Delta is less than zero, so there is no solution for the equation