1/9(2m-16)=1/3(2m

Solution for 1/9(2m-16)=1/3(2m equation:

1/9(2m-16)=1/3(2m

We move all terms to the left:

1/9(2m-16)-(1/3(2m)=0


Domain of the equation: 9(2m-16)!=0

m∈R



Domain of the equation: 32m!=0

m!=0/32

m!=0

m∈R


We calculate fractions


32m/(576m^2-4608m)+(-9m2/(576m^2-4608m)=0


We calculate terms in parentheses: +(-9m2/(576m^2-4608m), so:

-9m2/(576m^2-4608m

We multiply all the terms by the denominator


-9m2

We add all the numbers together, and all the variables

-9m^2

Back to the equation:

+(-9m^2)


We get rid of parentheses

-9m^2+32m/(576m^2-4608m)=0

We multiply all the terms by the denominator


-9m^2*(576m^2-4608m)+32m=0