1/9(2y-1)=1/3(y+1)

Solution for 1/9(2y-1)=1/3(y+1) equation:

1/9(2y-1)=1/3(y+1)

We move all terms to the left:

1/9(2y-1)-(1/3(y+1))=0


Domain of the equation: 9(2y-1)!=0

y∈R



Domain of the equation: 3(y+1))!=0

y∈R


We calculate fractions


(3yy/(9(2y-1)*3(y+1)))+(-9y2/(9(2y-1)*3(y+1)))=0


We calculate terms in parentheses: +(3yy/(9(2y-1)*3(y+1))), so:

3yy/(9(2y-1)*3(y+1))

We multiply all the terms by the denominator


3yy

Back to the equation:

+(3yy)



We calculate terms in parentheses: +(-9y2/(9(2y-1)*3(y+1))), so:

-9y2/(9(2y-1)*3(y+1))

We multiply all the terms by the denominator


-9y2

We add all the numbers together, and all the variables

-9y^2

Back to the equation:

+(-9y^2)


We get rid of parentheses

-9y^2+3yy=0