1/9(6t-7)=t+7/18

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Solution for 1/9(6t-7)=t+7/18 equation: 


t in (-oo:+oo)

(1/9)*(6*t-7) = t+7/18 // - t+7/18

(1/9)*(6*t-7)-t-(7/18) = 0

(1/9)*(6*t-7)-t-7/18 = 0

1/9*(6*t-7)-t-7/18 = 0

(1/9*18*(6*t-7))/18+(18*(-t))/18-7/18 = 0

1/9*18*(6*t-7)+18*(-t)-7 = 0

-6*t-14-7 = 0

-6*t-21 = 0

(-6*t-21)/18 = 0

(-6*t-21)/18 = 0 // * 18

-6*t-21 = 0

-6*t-21 = 0 // + 21

-6*t = 21 // : -6

t = 21/(-6)

t = -7/2

t = -7/2

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